# Subtle Art of De-MOSS-ing

Ever since it’s introduction in 1994, Stanford’s MOSS, or Measure of Software Similarity, has been an integral part of programming classes worldwide to detect plagiarism in coding assignments. It’s an effective measure, a good system, but, it’s not perfect.

Stanford’s MOSS is beatable.

In this article, I aim to accumulate all knows techniques of beating MOSS, summarize knowledge from various sources, and bring it all together in one place. Though I would like to clarify that (most) assignments are an integral part of learning and this article has been written solely to satiate academic curiosity.

Original Sample Code:

`// Original Code#include <stdio.h>int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op) {        case 1: ans = a+b;                break;        case 2: ans = (int) abs(a-b);                break;        case 3: ans = a*b;                break;        case 4: ans = (int) pow(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`

# 1. The 0–1 Ruse

MOSS Check : 0% Similarity

`// Declarations made for one = 1 and zero = 0 and used as explained.#include <stdio.h>int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    int one = 1;    printf ("Enter second number: ");    scanf("%d", &b);    int zero = 0;    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op*one) {        case 1: ans = a*one+b + zero;                break;        case 2: ans = (int) abs(a-b*one)+ zero;                break;        case 3: ans = a*one*b+ zero;                break;        case 4: ans = (int) pow(a*one,b)+ zero;                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans*one + zero);    return 0;}`

# 2. Changing Workflow

MOSS Check : 0% Similarity

`// Code with workflow changed.#include <stdio.h>int main() {    int a;    printf ("Enter first number: ");    scanf("%d", &a);    int b;    printf ("Enter second number: ");    scanf("%d", &b);    int ans;    while (1) {        printf("Choose what you want to do:\n1 for a*b\n2 for a+b\n3 for a^b\n4 for a~b\n");        int op;        int flag = 0;        scanf ("%d", &op);        switch (op) {            case 3: ans = (int) pow(a,b);                    break;            case 1: ans = a*b;                    break;            case 4: ans = (int) abs(a-b);                    break;            case 2: ans = a+b;                    break;            default: printf ("\nChoose a Valid Operator\n");                    flag = 1;        }        if (!flag){            break;        }    }    printf ("The answer is : %d\n", ans);    return 0;}`

MOSS Check : 0% Similarity

`// Variables replaced by single value arrays#include <stdio.h>int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op) {        case 1: ans = a+b;                break;        case 2: ans = (int) abs(a-b);                break;        case 3: ans = a*b;                break;        case 4: ans = (int) pow(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`

# 4. Altering Datatypes

MOSS Check : 50% Similarity

`/ INT changed to LONG IT#include <stdio.h>int main() {    long int a,b,op,ans;    printf ("Enter first number: ");    scanf("%ld", &a);    printf ("Enter second number: ");    scanf("%ld", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%ld", &op);    switch (op) {        case 1: ans = a+b;                break;        case 2: ans = (long int) abs(a-b);                break;        case 3: ans = a*b;                break;        case 4: ans = (long int) pow(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %ld\n", ans);    return 0;}`

# 5. Exploring New Dimensions

MOSS Check : 0% Similarity

`// Modified Code with single point 2D Arrays#include <stdio.h>int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op) {        case 1: ans = a+b;                break;        case 2: ans = (int) abs(a-b);                break;        case 3: ans = a*b;                break;        case 4: ans = (int) pow(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`

# 6. Modifying Conditions

MOSS Check : 34% Similarity

`// Switch statement changed to if-else-if steps.#include <stdio.h>int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    if (op == 1)        ans = a+b;    else if (op == 2)        ans = (int) abs(a-b);    else if (op == 3)        ans = a*b;    else if (op == 4)        ans = (int) pow(a,b);    else {        printf ("\nChoose a Valid Operator\n");        goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`

# 7. Manipulating Loops

MOSS Check : 68% Similarity
A single line changed and similarity reduced by 32%.

`// Infinite while loop changed to an infinite for loop#include <stdio.h>int main() {    int a;    printf ("Enter first number: ");    scanf("%d", &a);    int b;    printf ("Enter second number: ");    scanf("%d", &b);    int ans;    for (int i = 0; ; i++) {        printf("Choose what you want to do:\n1 for a*b\n2 for a+b\n3 for a^b\n4 for a~b\n");        int op;        int flag = 0;        scanf ("%d", &op);        switch (op) {            case 3: ans = (int) pow(a,b);                    break;            case 1: ans = a*b;                    break;            case 4: ans = (int) abs(a-b);                    break;            case 2: ans = a+b;                    break;            default: printf ("\nChoose a Valid Operator\n");                    flag = 1;        }        if (!flag){            break;        }    }    printf ("The answer is : %d\n", ans);    return 0;}`

# 8. Modularity

MOSS Check: 21% Similarity

`// Modular functions added for each operation.#include <stdio.h>int add (int a, int b) {    int c = a+b;    return c;}int difference (int a, int b) {    int c = (int) abs(a-b);    return c;}int product (int a, int b) {    int c = a*b;    return c;}int exponential (int a, int b) {    int c = (int) pow(a,b);    return c;}int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op) {        case 1: ans = add(a,b);                break;        case 2: ans = difference(a,b);                break;        case 3: ans = product(a,b);                break;        case 4: ans = exponential(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`

`// Entire Mergesort funciton hard coded and added to the original code.#include <stdio.h>void merge(int arr[], int l, int m, int r){    int i, j, k;    int n1 = m - l + 1;    int n2 =  r - m;    int L[n1], R[n2];    for (i = 0; i < n1; i++)        L[i] = arr[l + i];    for (j = 0; j < n2; j++)        R[j] = arr[m + 1+ j];    i = 0; // Initial index of first subarray    j = 0; // Initial index of second subarray    k = l; // Initial index of merged subarray    while (i < n1 && j < n2) {        if (L[i] <= R[j]) {            arr[k] = L[i];            i++;        }        else {            arr[k] = R[j];            j++;        }        k++;    }    while (i < n1) {        arr[k] = L[i];        i++;        k++;    }    while (j < n2) {        arr[k] = R[j];        j++;        k++;    }}void mergeSort(int arr[], int l, int r) {    if (l < r) {        int m = l+(r-l)/2;        mergeSort(arr, l, m);        mergeSort(arr, m+1, r);        merge(arr, l, m, r);    }}void printArray(int A[], int size) {    int i;    for (i=0; i < size; i++)        printf("%d ", A[i]);    printf("\n");}int main() {    int a,b,op,ans;    printf ("Enter first number: ");    scanf("%d", &a);    printf ("Enter second number: ");    scanf("%d", &b);    here:    printf("Choose what you want to do:\n1 for a+b\n2 for a~b\n3 for a*b\n4 for a^b\n");    scanf ("%d", &op);    switch (op) {        case 1: ans = a+b;                break;        case 2: ans = (int) abs(a-b);                break;        case 3: ans = a*b;                break;        case 4: ans = (int) pow(a,b);                break;        default: printf ("\nChoose a Valid Operator\n");                goto here;    }    printf ("The answer is : %d\n", ans);    return 0;}`